C code to calculate product of even digits of a given number

 C code to calculate product of even digits of a given number

Code Steps:

1. First input the number
2. Now initialize a variable =1, that stores the multiplication 
3. Now start a while loop until number = 0
4. Inside while loop just find out all the digits by finding the remainder & check it if it is divisible by 2 
5. If the number is divisible by 2 then multiply that number with the variable that was initialize = 1
6. At last return the multiplication storing variable. 

C Code Snippet

#include<stdio.h>

int main (){

    int num;

    int product = 1;

    printf("Enter the number: ");

    scanf("%d",&num);

    int temp = num;

    while(num != 0){

       

        int digit = num % 10;

        num = num / 10;

        if(digit%2==0){

            product = digit*product;

        }

    }

    printf("The product of even digits of %d is: %d", temp,product);

    return 0;

}

Input Output

Enter the number: 78254

The product of even digits of 78254 is: 64

Explanation: 8*2*4 = 64

Enter the number: 589

The product of even digits of 589 is: 8

Explanation: 8*1 = 8